200x^2+15000x+1=73

Solution for 200x^2+15000x+1=73 equation:

200x^2+15000x+1=73

We move all terms to the left:

200x^2+15000x+1-(73)=0

We add all the numbers together, and all the variables

200x^2+15000x-72=0

a = 200; b = 15000; c = -72;
Δ = b2-4ac
Δ = 150002-4·200·(-72)
Δ = 225057600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{225057600}=\sqrt{14400*15629}=\sqrt{14400}*\sqrt{15629}=120\sqrt{15629}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15000)-120\sqrt{15629}}{2*200}=\frac{-15000-120\sqrt{15629}}{400}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15000)+120\sqrt{15629}}{2*200}=\frac{-15000+120\sqrt{15629}}{400}
$